The math is wrong. As soon as one door is opened the chances automatically change to 50/50, because there are only TWO doors left, the first open door is no longer in contention.
Also, before opening a single door, if you adopt the strategy of switching doors after picking the first one, your chances of success are 66%. this is BEFORE YOU OPEN ANYTHING. Of course the chances revert to 50% after a door is opened! What this video proves is that if you decide to ALWAYS switch doors, BEFORE you actually open anything, you will have a higher chance of success.
I hereby Post first!! under article 125 section 4 paragraph 6 ! Any glumerterians failing to claim posting first after doing thereof,so gives up that post or any claim of post thereafter on the thread thus in dispute!!
Another way of proving the hypotheis is to illustrate the problem by keeping the location of the car and goats constant but choosing a different door each time you play. Let's say the car is behind door three and the goats are behind doors one and two. You have three initial choices. If you pick door one first, Monty would open door two. If you stay with door one you get a goat, if you swich to door three, you get the car. If you pick door two first, Monty reveals a goat behind door one and once again you lose if you don't switch. However, if you pick door number three first, you lose if you switch and win if you stay. So, out of your three initial choices, switching would result in winning twice and losing once.
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